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Note that arrows (\(\to\)) in type theory are always right associative; \(A \to B \to C\) means \(A \to (B \to C)\). This convention is the one which plays well with currying; \((A \to (B \to C)) \cong ((A \times B) \to C)\) ↩︎
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by z411 @ 2026-03-10
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Applying the lowest January 2026 US spot prices we get: